Optimal. Leaf size=1225 \[ -\frac {(5 b c-4 a d) \sqrt {c+d x^4}}{4 a^2 c (b c-a d) x}+\frac {\sqrt {d} (5 b c-4 a d) x \sqrt {c+d x^4}}{4 a^2 c (b c-a d) \left (\sqrt {c}+\sqrt {d} x^2\right )}+\frac {b \sqrt {c+d x^4}}{4 a (b c-a d) x \left (a+b x^4\right )}-\frac {b^{3/4} (5 b c-7 a d) \tan ^{-1}\left (\frac {\sqrt {b c-a d} x}{\sqrt [4]{-a} \sqrt [4]{b} \sqrt {c+d x^4}}\right )}{16 (-a)^{9/4} (b c-a d)^{3/2}}-\frac {b^{3/4} (5 b c-7 a d) \tan ^{-1}\left (\frac {\sqrt {-b c+a d} x}{\sqrt [4]{-a} \sqrt [4]{b} \sqrt {c+d x^4}}\right )}{16 (-a)^{9/4} (-b c+a d)^{3/2}}-\frac {\sqrt [4]{d} (5 b c-4 a d) \left (\sqrt {c}+\sqrt {d} x^2\right ) \sqrt {\frac {c+d x^4}{\left (\sqrt {c}+\sqrt {d} x^2\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{d} x}{\sqrt [4]{c}}\right )|\frac {1}{2}\right )}{4 a^2 c^{3/4} (b c-a d) \sqrt {c+d x^4}}+\frac {\sqrt [4]{d} (5 b c-4 a d) \left (\sqrt {c}+\sqrt {d} x^2\right ) \sqrt {\frac {c+d x^4}{\left (\sqrt {c}+\sqrt {d} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{d} x}{\sqrt [4]{c}}\right )|\frac {1}{2}\right )}{8 a^2 c^{3/4} (b c-a d) \sqrt {c+d x^4}}+\frac {b \left (\sqrt {c}-\frac {\sqrt {-a} \sqrt {d}}{\sqrt {b}}\right ) \sqrt [4]{d} (5 b c-7 a d) \left (\sqrt {c}+\sqrt {d} x^2\right ) \sqrt {\frac {c+d x^4}{\left (\sqrt {c}+\sqrt {d} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{d} x}{\sqrt [4]{c}}\right )|\frac {1}{2}\right )}{16 a^2 \sqrt [4]{c} (b c-a d) (b c+a d) \sqrt {c+d x^4}}+\frac {b \left (\sqrt {c}+\frac {\sqrt {-a} \sqrt {d}}{\sqrt {b}}\right ) \sqrt [4]{d} (5 b c-7 a d) \left (\sqrt {c}+\sqrt {d} x^2\right ) \sqrt {\frac {c+d x^4}{\left (\sqrt {c}+\sqrt {d} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{d} x}{\sqrt [4]{c}}\right )|\frac {1}{2}\right )}{16 a^2 \sqrt [4]{c} (b c-a d) (b c+a d) \sqrt {c+d x^4}}-\frac {\sqrt {b} \left (\sqrt {b} \sqrt {c}+\sqrt {-a} \sqrt {d}\right )^2 (5 b c-7 a d) \left (\sqrt {c}+\sqrt {d} x^2\right ) \sqrt {\frac {c+d x^4}{\left (\sqrt {c}+\sqrt {d} x^2\right )^2}} \Pi \left (-\frac {\left (\sqrt {b} \sqrt {c}-\sqrt {-a} \sqrt {d}\right )^2}{4 \sqrt {-a} \sqrt {b} \sqrt {c} \sqrt {d}};2 \tan ^{-1}\left (\frac {\sqrt [4]{d} x}{\sqrt [4]{c}}\right )|\frac {1}{2}\right )}{32 (-a)^{5/2} \sqrt [4]{c} \sqrt [4]{d} (b c-a d) (b c+a d) \sqrt {c+d x^4}}+\frac {\sqrt {b} \left (\sqrt {b} \sqrt {c}-\sqrt {-a} \sqrt {d}\right )^2 (5 b c-7 a d) \left (\sqrt {c}+\sqrt {d} x^2\right ) \sqrt {\frac {c+d x^4}{\left (\sqrt {c}+\sqrt {d} x^2\right )^2}} \Pi \left (\frac {\left (\sqrt {b} \sqrt {c}+\sqrt {-a} \sqrt {d}\right )^2}{4 \sqrt {-a} \sqrt {b} \sqrt {c} \sqrt {d}};2 \tan ^{-1}\left (\frac {\sqrt [4]{d} x}{\sqrt [4]{c}}\right )|\frac {1}{2}\right )}{32 (-a)^{5/2} \sqrt [4]{c} \sqrt [4]{d} (b c-a d) (b c+a d) \sqrt {c+d x^4}} \]
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Rubi [A]
time = 1.39, antiderivative size = 1225, normalized size of antiderivative = 1.00, number of steps
used = 14, number of rules used = 9, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.375, Rules used = {483, 597, 598,
311, 226, 1210, 504, 1231, 1721} \begin {gather*} \frac {\sqrt {b} (5 b c-7 a d) \left (\sqrt {d} x^2+\sqrt {c}\right ) \sqrt {\frac {d x^4+c}{\left (\sqrt {d} x^2+\sqrt {c}\right )^2}} \Pi \left (\frac {\left (\sqrt {b} \sqrt {c}+\sqrt {-a} \sqrt {d}\right )^2}{4 \sqrt {-a} \sqrt {b} \sqrt {c} \sqrt {d}};2 \text {ArcTan}\left (\frac {\sqrt [4]{d} x}{\sqrt [4]{c}}\right )|\frac {1}{2}\right ) \left (\sqrt {b} \sqrt {c}-\sqrt {-a} \sqrt {d}\right )^2}{32 (-a)^{5/2} \sqrt [4]{c} \sqrt [4]{d} (b c-a d) (b c+a d) \sqrt {d x^4+c}}-\frac {b^{3/4} (5 b c-7 a d) \text {ArcTan}\left (\frac {\sqrt {b c-a d} x}{\sqrt [4]{-a} \sqrt [4]{b} \sqrt {d x^4+c}}\right )}{16 (-a)^{9/4} (b c-a d)^{3/2}}-\frac {b^{3/4} (5 b c-7 a d) \text {ArcTan}\left (\frac {\sqrt {a d-b c} x}{\sqrt [4]{-a} \sqrt [4]{b} \sqrt {d x^4+c}}\right )}{16 (-a)^{9/4} (a d-b c)^{3/2}}-\frac {\sqrt [4]{d} (5 b c-4 a d) \left (\sqrt {d} x^2+\sqrt {c}\right ) \sqrt {\frac {d x^4+c}{\left (\sqrt {d} x^2+\sqrt {c}\right )^2}} E\left (2 \text {ArcTan}\left (\frac {\sqrt [4]{d} x}{\sqrt [4]{c}}\right )|\frac {1}{2}\right )}{4 a^2 c^{3/4} (b c-a d) \sqrt {d x^4+c}}+\frac {\sqrt [4]{d} (5 b c-4 a d) \left (\sqrt {d} x^2+\sqrt {c}\right ) \sqrt {\frac {d x^4+c}{\left (\sqrt {d} x^2+\sqrt {c}\right )^2}} F\left (2 \text {ArcTan}\left (\frac {\sqrt [4]{d} x}{\sqrt [4]{c}}\right )|\frac {1}{2}\right )}{8 a^2 c^{3/4} (b c-a d) \sqrt {d x^4+c}}+\frac {b \left (\sqrt {c}-\frac {\sqrt {-a} \sqrt {d}}{\sqrt {b}}\right ) \sqrt [4]{d} (5 b c-7 a d) \left (\sqrt {d} x^2+\sqrt {c}\right ) \sqrt {\frac {d x^4+c}{\left (\sqrt {d} x^2+\sqrt {c}\right )^2}} F\left (2 \text {ArcTan}\left (\frac {\sqrt [4]{d} x}{\sqrt [4]{c}}\right )|\frac {1}{2}\right )}{16 a^2 \sqrt [4]{c} (b c-a d) (b c+a d) \sqrt {d x^4+c}}+\frac {b \left (\sqrt {c}+\frac {\sqrt {-a} \sqrt {d}}{\sqrt {b}}\right ) \sqrt [4]{d} (5 b c-7 a d) \left (\sqrt {d} x^2+\sqrt {c}\right ) \sqrt {\frac {d x^4+c}{\left (\sqrt {d} x^2+\sqrt {c}\right )^2}} F\left (2 \text {ArcTan}\left (\frac {\sqrt [4]{d} x}{\sqrt [4]{c}}\right )|\frac {1}{2}\right )}{16 a^2 \sqrt [4]{c} (b c-a d) (b c+a d) \sqrt {d x^4+c}}-\frac {\sqrt {b} \left (\sqrt {b} \sqrt {c}+\sqrt {-a} \sqrt {d}\right )^2 (5 b c-7 a d) \left (\sqrt {d} x^2+\sqrt {c}\right ) \sqrt {\frac {d x^4+c}{\left (\sqrt {d} x^2+\sqrt {c}\right )^2}} \Pi \left (-\frac {\left (\sqrt {b} \sqrt {c}-\sqrt {-a} \sqrt {d}\right )^2}{4 \sqrt {-a} \sqrt {b} \sqrt {c} \sqrt {d}};2 \text {ArcTan}\left (\frac {\sqrt [4]{d} x}{\sqrt [4]{c}}\right )|\frac {1}{2}\right )}{32 (-a)^{5/2} \sqrt [4]{c} \sqrt [4]{d} (b c-a d) (b c+a d) \sqrt {d x^4+c}}-\frac {(5 b c-4 a d) \sqrt {d x^4+c}}{4 a^2 c (b c-a d) x}+\frac {\sqrt {d} (5 b c-4 a d) x \sqrt {d x^4+c}}{4 a^2 c (b c-a d) \left (\sqrt {d} x^2+\sqrt {c}\right )}+\frac {b \sqrt {d x^4+c}}{4 a (b c-a d) x \left (b x^4+a\right )} \end {gather*}
Antiderivative was successfully verified.
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Rule 226
Rule 311
Rule 483
Rule 504
Rule 597
Rule 598
Rule 1210
Rule 1231
Rule 1721
Rubi steps
\begin {align*} \int \frac {1}{x^2 \left (a+b x^4\right )^2 \sqrt {c+d x^4}} \, dx &=\frac {b \sqrt {c+d x^4}}{4 a (b c-a d) x \left (a+b x^4\right )}-\frac {\int \frac {-5 b c+4 a d-3 b d x^4}{x^2 \left (a+b x^4\right ) \sqrt {c+d x^4}} \, dx}{4 a (b c-a d)}\\ &=-\frac {(5 b c-4 a d) \sqrt {c+d x^4}}{4 a^2 c (b c-a d) x}+\frac {b \sqrt {c+d x^4}}{4 a (b c-a d) x \left (a+b x^4\right )}+\frac {\int \frac {x^2 \left (-(b c-2 a d) (5 b c-2 a d)+b d (5 b c-4 a d) x^4\right )}{\left (a+b x^4\right ) \sqrt {c+d x^4}} \, dx}{4 a^2 c (b c-a d)}\\ &=-\frac {(5 b c-4 a d) \sqrt {c+d x^4}}{4 a^2 c (b c-a d) x}+\frac {b \sqrt {c+d x^4}}{4 a (b c-a d) x \left (a+b x^4\right )}+\frac {\int \left (\frac {d (5 b c-4 a d) x^2}{\sqrt {c+d x^4}}+\frac {\left (-5 b^2 c^2+7 a b c d\right ) x^2}{\left (a+b x^4\right ) \sqrt {c+d x^4}}\right ) \, dx}{4 a^2 c (b c-a d)}\\ &=-\frac {(5 b c-4 a d) \sqrt {c+d x^4}}{4 a^2 c (b c-a d) x}+\frac {b \sqrt {c+d x^4}}{4 a (b c-a d) x \left (a+b x^4\right )}-\frac {(b (5 b c-7 a d)) \int \frac {x^2}{\left (a+b x^4\right ) \sqrt {c+d x^4}} \, dx}{4 a^2 (b c-a d)}+\frac {(d (5 b c-4 a d)) \int \frac {x^2}{\sqrt {c+d x^4}} \, dx}{4 a^2 c (b c-a d)}\\ &=-\frac {(5 b c-4 a d) \sqrt {c+d x^4}}{4 a^2 c (b c-a d) x}+\frac {b \sqrt {c+d x^4}}{4 a (b c-a d) x \left (a+b x^4\right )}+\frac {\left (\sqrt {b} (5 b c-7 a d)\right ) \int \frac {1}{\left (\sqrt {-a}-\sqrt {b} x^2\right ) \sqrt {c+d x^4}} \, dx}{8 a^2 (b c-a d)}-\frac {\left (\sqrt {b} (5 b c-7 a d)\right ) \int \frac {1}{\left (\sqrt {-a}+\sqrt {b} x^2\right ) \sqrt {c+d x^4}} \, dx}{8 a^2 (b c-a d)}+\frac {\left (\sqrt {d} (5 b c-4 a d)\right ) \int \frac {1}{\sqrt {c+d x^4}} \, dx}{4 a^2 \sqrt {c} (b c-a d)}-\frac {\left (\sqrt {d} (5 b c-4 a d)\right ) \int \frac {1-\frac {\sqrt {d} x^2}{\sqrt {c}}}{\sqrt {c+d x^4}} \, dx}{4 a^2 \sqrt {c} (b c-a d)}\\ &=-\frac {(5 b c-4 a d) \sqrt {c+d x^4}}{4 a^2 c (b c-a d) x}+\frac {\sqrt {d} (5 b c-4 a d) x \sqrt {c+d x^4}}{4 a^2 c (b c-a d) \left (\sqrt {c}+\sqrt {d} x^2\right )}+\frac {b \sqrt {c+d x^4}}{4 a (b c-a d) x \left (a+b x^4\right )}-\frac {\sqrt [4]{d} (5 b c-4 a d) \left (\sqrt {c}+\sqrt {d} x^2\right ) \sqrt {\frac {c+d x^4}{\left (\sqrt {c}+\sqrt {d} x^2\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{d} x}{\sqrt [4]{c}}\right )|\frac {1}{2}\right )}{4 a^2 c^{3/4} (b c-a d) \sqrt {c+d x^4}}+\frac {\sqrt [4]{d} (5 b c-4 a d) \left (\sqrt {c}+\sqrt {d} x^2\right ) \sqrt {\frac {c+d x^4}{\left (\sqrt {c}+\sqrt {d} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{d} x}{\sqrt [4]{c}}\right )|\frac {1}{2}\right )}{8 a^2 c^{3/4} (b c-a d) \sqrt {c+d x^4}}+\frac {\left (b \sqrt {c} \left (\sqrt {b} \sqrt {c}-\sqrt {-a} \sqrt {d}\right ) (5 b c-7 a d)\right ) \int \frac {1+\frac {\sqrt {d} x^2}{\sqrt {c}}}{\left (\sqrt {-a}-\sqrt {b} x^2\right ) \sqrt {c+d x^4}} \, dx}{8 a^2 (b c-a d) (b c+a d)}-\frac {\left (b \sqrt {c} \left (\sqrt {b} \sqrt {c}+\sqrt {-a} \sqrt {d}\right ) (5 b c-7 a d)\right ) \int \frac {1+\frac {\sqrt {d} x^2}{\sqrt {c}}}{\left (\sqrt {-a}+\sqrt {b} x^2\right ) \sqrt {c+d x^4}} \, dx}{8 a^2 (b c-a d) (b c+a d)}+\frac {\left (\sqrt {b} \left (\sqrt {b} \sqrt {c}-\sqrt {-a} \sqrt {d}\right ) \sqrt {d} (5 b c-7 a d)\right ) \int \frac {1}{\sqrt {c+d x^4}} \, dx}{8 a^2 (b c-a d) (b c+a d)}+\frac {\left (\sqrt {b} \left (\sqrt {b} \sqrt {c}+\sqrt {-a} \sqrt {d}\right ) \sqrt {d} (5 b c-7 a d)\right ) \int \frac {1}{\sqrt {c+d x^4}} \, dx}{8 a^2 (b c-a d) (b c+a d)}\\ &=-\frac {(5 b c-4 a d) \sqrt {c+d x^4}}{4 a^2 c (b c-a d) x}+\frac {\sqrt {d} (5 b c-4 a d) x \sqrt {c+d x^4}}{4 a^2 c (b c-a d) \left (\sqrt {c}+\sqrt {d} x^2\right )}+\frac {b \sqrt {c+d x^4}}{4 a (b c-a d) x \left (a+b x^4\right )}-\frac {b^{3/4} (5 b c-7 a d) \tan ^{-1}\left (\frac {\sqrt {b c-a d} x}{\sqrt [4]{-a} \sqrt [4]{b} \sqrt {c+d x^4}}\right )}{16 (-a)^{9/4} (b c-a d)^{3/2}}-\frac {b^{3/4} (5 b c-7 a d) \tan ^{-1}\left (\frac {\sqrt {-b c+a d} x}{\sqrt [4]{-a} \sqrt [4]{b} \sqrt {c+d x^4}}\right )}{16 (-a)^{9/4} (-b c+a d)^{3/2}}-\frac {\sqrt [4]{d} (5 b c-4 a d) \left (\sqrt {c}+\sqrt {d} x^2\right ) \sqrt {\frac {c+d x^4}{\left (\sqrt {c}+\sqrt {d} x^2\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{d} x}{\sqrt [4]{c}}\right )|\frac {1}{2}\right )}{4 a^2 c^{3/4} (b c-a d) \sqrt {c+d x^4}}+\frac {\sqrt [4]{d} (5 b c-4 a d) \left (\sqrt {c}+\sqrt {d} x^2\right ) \sqrt {\frac {c+d x^4}{\left (\sqrt {c}+\sqrt {d} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{d} x}{\sqrt [4]{c}}\right )|\frac {1}{2}\right )}{8 a^2 c^{3/4} (b c-a d) \sqrt {c+d x^4}}+\frac {\sqrt {b} \left (\sqrt {b} \sqrt {c}-\sqrt {-a} \sqrt {d}\right ) \sqrt [4]{d} (5 b c-7 a d) \left (\sqrt {c}+\sqrt {d} x^2\right ) \sqrt {\frac {c+d x^4}{\left (\sqrt {c}+\sqrt {d} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{d} x}{\sqrt [4]{c}}\right )|\frac {1}{2}\right )}{16 a^2 \sqrt [4]{c} (b c-a d) (b c+a d) \sqrt {c+d x^4}}+\frac {\sqrt {b} \left (\sqrt {b} \sqrt {c}+\sqrt {-a} \sqrt {d}\right ) \sqrt [4]{d} (5 b c-7 a d) \left (\sqrt {c}+\sqrt {d} x^2\right ) \sqrt {\frac {c+d x^4}{\left (\sqrt {c}+\sqrt {d} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{d} x}{\sqrt [4]{c}}\right )|\frac {1}{2}\right )}{16 a^2 \sqrt [4]{c} (b c-a d) (b c+a d) \sqrt {c+d x^4}}-\frac {\sqrt {b} \left (\sqrt {b} \sqrt {c}+\sqrt {-a} \sqrt {d}\right )^2 (5 b c-7 a d) \left (\sqrt {c}+\sqrt {d} x^2\right ) \sqrt {\frac {c+d x^4}{\left (\sqrt {c}+\sqrt {d} x^2\right )^2}} \Pi \left (-\frac {\left (\sqrt {b} \sqrt {c}-\sqrt {-a} \sqrt {d}\right )^2}{4 \sqrt {-a} \sqrt {b} \sqrt {c} \sqrt {d}};2 \tan ^{-1}\left (\frac {\sqrt [4]{d} x}{\sqrt [4]{c}}\right )|\frac {1}{2}\right )}{32 (-a)^{5/2} \sqrt [4]{c} \sqrt [4]{d} (b c-a d) (b c+a d) \sqrt {c+d x^4}}+\frac {\sqrt {b} \left (\sqrt {b} \sqrt {c}-\sqrt {-a} \sqrt {d}\right )^2 (5 b c-7 a d) \left (\sqrt {c}+\sqrt {d} x^2\right ) \sqrt {\frac {c+d x^4}{\left (\sqrt {c}+\sqrt {d} x^2\right )^2}} \Pi \left (\frac {\left (\sqrt {b} \sqrt {c}+\sqrt {-a} \sqrt {d}\right )^2}{4 \sqrt {-a} \sqrt {b} \sqrt {c} \sqrt {d}};2 \tan ^{-1}\left (\frac {\sqrt [4]{d} x}{\sqrt [4]{c}}\right )|\frac {1}{2}\right )}{32 (-a)^{5/2} \sqrt [4]{c} \sqrt [4]{d} (b c-a d) (b c+a d) \sqrt {c+d x^4}}\\ \end {align*}
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Mathematica [C] Result contains higher order function than in optimal. Order 6 vs. order 4 in
optimal.
time = 10.20, size = 226, normalized size = 0.18 \begin {gather*} \frac {21 a \left (c+d x^4\right ) \left (4 a^2 d-5 b^2 c x^4-4 a b \left (c-d x^4\right )\right )-7 \left (5 b^2 c^2-12 a b c d+4 a^2 d^2\right ) x^4 \left (a+b x^4\right ) \sqrt {1+\frac {d x^4}{c}} F_1\left (\frac {3}{4};\frac {1}{2},1;\frac {7}{4};-\frac {d x^4}{c},-\frac {b x^4}{a}\right )+3 b d (5 b c-4 a d) x^8 \left (a+b x^4\right ) \sqrt {1+\frac {d x^4}{c}} F_1\left (\frac {7}{4};\frac {1}{2},1;\frac {11}{4};-\frac {d x^4}{c},-\frac {b x^4}{a}\right )}{84 a^3 c (b c-a d) x \left (a+b x^4\right ) \sqrt {c+d x^4}} \end {gather*}
Antiderivative was successfully verified.
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Maple [C] Result contains higher order function than in optimal. Order 9 vs. order
4.
time = 0.53, size = 674, normalized size = 0.55 Too large to display
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{x^{2} \left (a + b x^{4}\right )^{2} \sqrt {c + d x^{4}}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {1}{x^2\,{\left (b\,x^4+a\right )}^2\,\sqrt {d\,x^4+c}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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